HOME

Course Chapters

Calculator Fundamentals

Mathematics Review

Basic Concepts

Advanced Concepts


Section Tests

Pre-test

Post-test


Useful Materials

Glossary


Online Calculators

Redox Calculator

Kinetics Arrhenius Calculator

Thermodynamics Calculator

Nuclear Decay Calculator

Linear Least Squares Regression

Newton's Method Equation Solver

Compressibility Calculator

Units Conversion Calculator

Nomenclature Calculator


Related Information Links

Texas Instruments Calculators

Casio Calculators

Sharp Calculators

Hewlett Packard Calculators


Credits

Credits

Contact Webmaster


Problem 2 Solution

(a) 4689 atoms   (b) 475 atoms

Solution Steps for Part (a):

If a sample of ammonia contains 1563 nitrogen atoms, how much hydrogen is present?

Answer:

We know the ratio of nitrogen to hydrogen atoms is 1 : 3, so we can set up the proportion:

Where x is the (unknown) amount of hydrogen atoms.

Cross multiplying gives x = 1563 * 3 or x = 4689.


Solution Steps for Part (b):

If a sample contains 1425 hydrogen atoms, how much nitrogen is present?

Answer:

We know the ratio of nitrogen to hydrogen atoms is 1 : 3, so we can set up the proportion:
Where this time x is the (unknown) amount of nitrogen atoms.

Cross multiplying gives 1425 = 3 x or (dividing by 3 on a calculator) x = 475.


Try another problem like this one.

Next Try It Out Problem.


Developed by
The Shodor Education Foundation, Inc.
in cooperation with the Department of Chemistry,
The University of North Carolina at Chapel Hill

Copyright © 1998
Last Update:
Please direct questions and comments about this page to
WebMaster@shodor.org