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Stoichiometry Solution:

If 2.0 moles of sucrose weighting 684 grams is put in 1000 grams of water
and is then dissolved, what would be the molality of the solution?

Answer=2.00 m
In this problem we use the equation for molality.
Molality=mols of solute/kilograms of solvent
We know the mols of solute =2 and the solvent weighs 1.00 liters. Therefore 2/1.00=2.00 m

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